[W1zzard]

Originally Posted by 3dc_member

	double memBw=c->m_busWidth*mem*1000^2/8./1024^3.;
	if (c->GetMemType().Find(_T("DDR"))!=-1)
		memBw*=2;
	if (c->GetMemType().Find(_T("DDR5"))!=-1)
		memBw*=2;

	m_result.Set(_T("MemBandwidth"), Format(_T("%.1f"), memBw));

and display it as GiB/s.
The current implementation is sheer nonsense.

that's the first useful feedback in this whole discussion, i will implement the quoted method, thanks for pointing out my error .. now people will cry some more for losing more bandwidth

i do disagree with 1 GB = 1024*1024*1024 being labeled as "GiB".. this whole GiB discussion is a complete waste of time. everybody serious uses it as "GB"