802.11ac modem/router

[JBG123]

I was looking for a router that is dual band and runs on 802.11ac then I realized I have some older appliances in my house that only run on 11g or 11n and that my computer is probably the only one that runs on 802.11ac if I were to buy a router that runs on ac what will happen to devices that run on g and n? Will my router downgrade to n/g?

Lastly, since most of the electronics run on 2.4GHZ in my house, is it completely pointless to get a dual band modem/router?

 

[FordGT90Concept]

g/n/ac shouldn't be a problem. Devices and the router auto-negotiate a protocol in the connection handshake. It's on a per-device basis so, no, the whole router shouldn't downgrade.

I have a 2.4/5 GHz router and there is literally nothing here on 5 GHz. Reason: signal strength is notably weaker. 5 GHz would work great for devices in the same room but 2.4 GHz is always going to have the bulk of devices simply because it penetrates obstacles better. For me, 5 GHz is not a priority. If you have so many devices that more channels are needed, I'd be more inclined to buy a 2.4 GHz access point than use 5 GHz.

 

[JBG123]

g/n/ac shouldn't be a problem. Devices and the router auto-negotiate a protocol in the connection handshake. It's on a per-device basis so, no, the whole router shouldn't downgrade.

I have a 2.4/5 GHz router and there is literally nothing here on 5 GHz. Reason: signal strength is notably weaker. 5 GHz would work great for devices in the same room but 2.4 GHz is always going to have the bulk of devices simply because it penetrates obstacles better. For me, 5 GHz is not a priority. If you have so many devices that more channels are needed, I'd be more inclined to buy a 2.4 GHz access point than use 5 GHz.

So basically a AC modem/router will have all the other standards aswell?

 

[FordGT90Concept]

The only one I think that has fallen out of favor is 802.11b. If you're concerned about it, just check the specs on the router before buying. It should say explicitly which ones it supports.