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No idea how many watts this USB-C port will supply?

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I have an ASUS TUF A15 laptop (FA507 model - R7 7435HS & RTX 4060) and I plan on buying an Asus Zenscreen OLED to use with it.

This portable monitor is rated for 15w power draw and usually gets it's power via USB-C. I'd prefer this comes from the same USB-C that's providing it with display data from the laptop, so that I'm only having to deal with the one cable.

Now, there's a USB-C 3.2 Gen2 combo port on my laptop which supports Displayport and apparently also supports power delivery, although that's for charging the laptop - I doubt it applies for output from the laptop. I've attached a picture of how ASUS describe this port in the user manual.

I don't know how to find out what this port can supply. Can it do a display signal and at least 15w all over one cable? How would I find out?
 

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Yes, but that seems to indicate what you will need to power the laptop, not how much power that USB power can supply. Minimum spec of USB 3.2 Gen 2 is 7.5 watts (5V @ 1.5A).
Or it could be that 100watt rating.
The all knowledgeable internet seems to think USB-PD ports can generally deliver power in either direction depending on what's needed, and that the devices in question figure it out amongst themselves.
 
The only real way to know is to ask ASUS; it's really stupid that they don't specify the maximum power each USB-C PD port delivers, in the product literature.
 
Well, I have a USB-C to USB-C cable at home so I ran my own wee test. My Samsung A55E will only show fast charging if it's receiving 15 watts or higher. Plugged it into the laptop's DP Alt + Power Delivery USB-C port and it said fast charging. Which means it should be fine as it's supplying over 15 watts.
 
Well, I have a USB-C to USB-C cable at home so I ran my own wee test. My Samsung A55E will only show fast charging if it's receiving 15 watts or higher. Plugged it into the laptop's DP Alt + Power Delivery USB-C port and it said fast charging. Which means it should be fine as it's supplying over 15 watts.
Is there anything specified on the notebook's label? Devices that deliver power through USB-C (chargers, power banks) always have a list of available voltages, and maximum current at each voltage, printed on the label. Very fine print in dark grey on darker grey is the standard here, so it's easy to miss.
 
Is there anything specified on the notebook's label? Devices that deliver power through USB-C (chargers, power banks) always have a list of available voltages, and maximum current at each voltage, printed on the label. Very fine print in dark grey on darker grey is the standard here, so it's easy to miss.
I know the label you're meaning, usually on the bottom of the machine. I'll check later.

ok I've got the monitor after the test with my phone last night. Plugged it in, no issues with power delivery over USB-C on the Displayport alt-mode / PD port, so it's sorted, easy.
 
The power requirements for the display are "DC 5-12V, 2.0A" and the power consumption is "15W or less".
If it is 5V2.0A, it will be 10W... but it will probably still work.
The 15W is the maximum instantaneous power consumption, and it is expected that it will be less than 10W during normal operation.
(Because it is OLED, the maximum continuous power consumption can be seen when the screen brightness is at maximum and the entire screen is displayed in white.)

On the other hand, when I look at the USB connector on the PC... after all, the USB PD output specifications are unclear.
The minimum I can read are the following...
- It supports USB3.2 10Gbps, so it can output 5V0.9A.
- It uses a USB Type-C connector, so it supports either 5V1.5A or 5V3A according to the USB Type-C Current standard... but that's probably a standard that's been forgotten now.

Since the smartphone was able to be fast-charged at 15W, we can see that USB PD allows outputs of "5V3A", "9V1.67A or more", "15V1A or more", and "15W or more at any voltage and current with PPS".

I always hope that manufacturers will clearly display both the input and output requirements for USB PD...
 
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